PROFESSIONAL ACADEMIC STUDY RESOURCES WEBSITE +1 813 434 1028 proexpertwritings@hotmail.com
hi i need this hw
Description
Signed and unsigned binary numbers: 1) What is the range of unsigned 16 bit numbers in decimal and in binary? 2) Convert decimal 101 to an 8-bit binary number. 3) Convert decimal –101 as an 8 bit 2’s complement number. 4) What is the decimal value of the 2’s complement number 11011001? 5) What are the largest and smallest decimal values representable in 2’s complement using 8 bits? 6) What are the largest and smallest decimal values representable in 2’s complement using 32 bits? 7) How many values can be represented with 42 bits using 2’s complement? 8) Convert decimal 48 to an 8 bit binary number. 9) Convert decimal –48 to an 8 bit 2’s complement number. 10) Convert decimal 38 to an 8 bit binary number. 11) Convert decimal –38 to an 8 bit 2’s complement number. 12) What is the decimal value of the 8 bit 2’s complement number 1101 1001 13) What is the decimal value of the 8 bit 2’s complement number 1001 1000 14) What is the decimal value of the 16 bit 2’s complement number 1101 1001 1001 1000 15) What is the decimal value of the 16 bit 2’s complement number 0101 1001 1001 1000 16) What is the decimal value of the 8 bit 2’s complement number 0000 0101 Floating Point Formats: 17) The IEEE standard uses excess 127 format for exponents. What would be the decimal exponent value of 0110 1011? 18) The IEEE standard uses excess 127. Would excess 128 be better? Explain. 19) What is the range of exponent values possible using 6 exponent bits? What is the value of k in this “Excess k” format using the IEEE excess mapping scheme? 20) Consider the following floating point format: 1 sign bit, 4 exponent bits in excess 7 format, and 5 mantissa bits. What are the decimal values represented by the following: 1 1011 11100 0 0100 01011 1 1111 11000 0 0110 01001 21) Convert decimal 85.0 to this format. 22) Convert decimal 25.0 to this format. 23) Convert decimal 2.25 to this format. 24) Convert decimal 7.125 to this forma